Question

помогите пж 10;11;12 срочно помогитееен

Answer 1

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6c/(b-3c)^2

Answer 2

$10) = \frac{6c(b - 3c)}{ {(b - 3c)}^{2} } = \frac{6c}{b - 3c}$
$11) = \frac{(a + 5)(a + 5)}{(a + 5)(a - 5)} = \frac{a + 5}{a - 5}$
$12) = \frac{(a - b)( {a}^{2} + ab + {b}^{2}) }{a - b} = {a}^{2} + ab + {b}^{2}$