Question

Помогите пожалуйста.

Answer 1

$y=\frac{12}{\sqrt{6+x}}+\sqrt{11-x}\\\\OOF:\; \; \left \{ {{6+x\ \textgreater \ 0} \atop {11-x \geq 0}} \right.\; \left \{ {{x\ \textgreater \ -6} \atop {x \leq 11}} \right. \; \; \Rightarrow \; \; x\in (-6;11\, ]\\\\---(-6)\; /////////\; [\, 11\, ]---$