Question

38.4. Приведите алгебраическую дробь:

Answer 1

$\frac{2y}{a-b}=\frac{2y(a-b)}{(a-b)^2}\\\\\frac{-3x}{x+a}=\frac{-3x(x-a)}{x^2-a^2}\\\\\frac{5a}{y-1}=\frac{5a(y^2+y+1)}{y^3-1}\\\\\frac{4b}{a^2+ab+b^2}= \frac{4b(a-b)}{a^3-b^3}\\\\\frac{9y}{y-b}=\frac{-9y}{b-y}\\\\\frac{-5x}{x-10}=\frac{5x}{10-x}\\\\\frac{-4p}{p+2}=\frac{-4p(2-p)}{4-p^2}=\frac{4p(p-2)}{4-p^2}$