Question

РЕБЯТА НУЖНА ПОМОЩЬ!!!!!!!!

Answer 1

$\frac{a}{x-2} + \frac{b}{x+1} = \frac{a(x+1)+b(x-2)}{(x-2)(x+1)} = \frac{10x-14}{(x-2)(x+1)} \\ \\ ax+a+bx-2b=10x-14 \\ \\ x(a+b)+(a-2b)=10x-14 \\ \\ \left \{ {{a-2b=-14} \atop {a+b=10}} \right. \\ \\ \left \{ {{a=2b-14} \atop {2b-14+b=10}} \right. \\ \\ \left \{ {{a=2b-14} \atop {b=8}} \right. \left \{ {{a=2} \atop {b=8}} \right. \\ \\ \frac{2}{x-2} + \frac{8}{x+1} = \frac{2x+2+8x-16}{(x-2)(x+1)}= \frac{10x-14}{(x-2)(x+1)}$