Question

Решите плиз : x^2-19x+60=0

Answer 1

D=361-240=121
x1=4 x2=15 

Answer 2

$x^2-19x+60=0\\ x^2-4x-15x+60=0\\ x(x-4)-14(x-4)=0\\ (x-4)(x-15)=0\\ x-4=0---\ \textgreater \ x=4\\ x-15---\ \textgreater \ x=15\\ Otvet: x1=4\;\; ; \;\;x2=15$