Question

Помогите решить уравнение!!

Answer 1

$2^{6(x+1)} = 2^{3(4 \sqrt{x} )}$
$6(x+1) = 3*4 \sqrt{x}$
$6(x+1) = 12 \sqrt{x}$
$x+1 = 2 \sqrt{x}$
$\sqrt{x} ^{2} - 2 \sqrt{x} +1 = 0$
$( \sqrt{x} - 1) ^{2} = 0$
$\sqrt{x} - 1= 0$
$\sqrt{x} = 1$
$x = 1$

Ответ: 1

Answer 2

64^(x+1)=8^(4•√x)
8^(2(x+1)=8^(4•√x)
2(x+1)=4•x¹/²
4(x+1)²=16x
(x+1)²-4x=0
x²+2x+1-4x=0
x²-2x+1=0
(x-1)²=0;x-1=0;x=1