Question

y=2-x/3x+1 Найти производную.

Answer 1

$y= \frac{2-x}{3x+1} \\y'=\frac{(2-x)'(3x+1)-(2-x)(3x+1)'}{(3x+1)^2} =\frac{-(3x+1)-3(2-x)}{(3x+1)^2} =\frac{-3x-1-6+3x}{(3x+1)^2} =\\=-\frac{7}{(3x+1)^2}$