Question

Помогите решить! arctg (-√3) · arcctg (-1) - arcsin (-√3/2) · arccos (-√3/2) + arcctg(-1/√3)·arcsin (-√2/2)

Answer 1

Значения все табличные.
arctg(-√3)*arcctg(-1)-arcsin(-√3/2)*arccos(-√3/2)+arcctg(-1/√3)*arcsin(-√2/2)=
=(-Π/3)*(-Π/4)-(-Π/3)*(5Π/6)+(-Π/3)*(-Π/4)=
=Π^2/12+5Π^2/18+Π^2/12=3Π^2/36+10Π^2/36+3Π^2/36=16Π^2/36=4Π^2/9