Question

Сократите дроби: 2x^2-2xy-x+y/4x^2-1

Answer 1

2x^2-2xy-x+y/4x^2-1 = (2x(x-y)-(x-y))/4x^2-1 = (x-y)(2x-1)/(2x-1)(2x+1) = 
= (x-y)/(2x+1)

Answer 2

$\frac{2x^2-2xy-x+y}{4x^2-1} =\frac{2x(x-y)-(x-y)}{(2x-1)(2x+1)} =\frac{(x-y)(2x-1)}{(2x-1)(2x+1)} =\frac{x-y}{2x+1}$