Question

10sin(пи/2+альфа)+24cos(3пи-альфа) всё делённое на 7sin(5\2пи-альфа)

Answer 1

(10sin(p/2 + a) + 24cos(3p - a))/(7sin(5p/2 - a)) = (10cos(a) - 24cos(a))/(7cos(a)) = -2