Question

Вычислите: 81/88 * (6 целых - 1целая 13/15 * 1целую 19/21)

/ - это дробь

Answer 1

$\frac{81}{88}*(6 -1\frac{13}{15} *1 \frac{19}{21})=\frac{81}{88}*(6 -\frac{28}{15} *\frac{40}{21})= \frac{81}{88}*( \frac{6}{1} -\frac{4}{3} *\frac{8}{3})=$$\frac{81}{88}*( \frac{6}{1} -\frac{32}{9})= \frac{81}{88}*( \frac{54}{9} - \frac{32}{9} )= \frac{81}{88} * \frac{22}{9} = \frac{9}{4} * \frac{1}{1} =2\frac{1}{4} =2,25$

Answer 2

$\frac{81}{88} (6-1 \frac{13}{15} *1 \frac{19}{21} )= \frac{81}{88}(6- \frac{28}{15} * \frac{40}{21})= \frac{81}{88} (6- \frac{4}{3}* \frac{8}{3} )= \frac{81}{88} (6- \frac{32}{9})=$
$\frac{81}{88} ( \frac{54}{9} - \frac{32}{9} )= \frac{81}{88} * \frac{22}{9}= \frac{9}{4}$

Ответ: $\frac{9}{4}$ или $2 \frac{1}{4}$ или 2.25