Question

помогите решить
$\frac{3x + 1}{x - 2} = \frac{2x - 10}{x + 1}$

Answer 1

$\frac{3x + 1}{x - 2} = \frac{2x - 10}{x + 1} \\ (3x+1)(x+1) = (2x-10)(x-2) \\ 3x^2 + 4 x + 1 = 2 x^2 - 14 x + 20 \\ x^2 + 18x - 19 = 0$
$\sqrt{D} = \sqrt{324+76} = \sqrt{400} = 20$
$x_1 = \frac{-18-20}{2} = -19 \\ x_2 = \frac{-18+20}{2} = 1$