Question

решите неравенство
х2+2х-3
------------ >0
х+1.

Answer 1

$\frac{x^2+2x-3}{x+1} \ \textgreater \ 0 \\ \\ \frac{x^2+3x-x-3}{x+1} \ \textgreater \ 0 \\ \\ \frac{(x+3(x-1)}{x+1} \ \textgreater \ 0 \\ \\ ----(-3)++++(-1)----(1)++++$

x∈(-3;-1)U(1;+∞)