Question

найдите производную
у=3-tgx +sin x

Answer 1

$f=3-tg(x)+sin(x) \\ \\ f'=(3)'-(tg(x))'+(sin(x))'=0- \frac{1}{cos^2(x)}+cos(x) \\ \\ \boxed {f'=cos(x)- \frac{1}{cos^2(x)} }$