Question

Решите неравенства
2,4

Answer 1

$2)-2x^2-x+6 \geq 0\\2x^2+x-6 \leq 0\\2x^2+x-6=0\\D=1+48=49\\x_1=\frac{-1+7}{4} =1,5\\x_2=-2\\-2 \leq x \leq 1,5\\4)2x^2-7x+6 \leq 0\\2x^2-7x+6=0\\D=49-48=1\\x_1=\frac{7+1}{4} =2\\x_1=1,5\\1,5 \leq x \leq 2$