Question

Помогите решить неравенства, пожалуйста. Очень срочно!!!

Answer 1

1)$2^{5x+3} \ \textless \ 2^{-2(2x+1)/x} \\ \\ 2\ \textgreater \ 1 \\ \\ 5x+3\ \textless \ \frac{-4x-2}{x} \\ \\ \frac{5x^2+7x+2}{x} \ \textless \ 0 \\ \\ D=9 \\ \\ x_{1} =-1 \\ \\ x_{2} =-2/5$

-----(-1)++++(-2/5)------(0)+++++++
x∈(-∞;-1)U(-2/5;0)

2)
$3^{2x-3} \ \textgreater \ 3^{ \frac{2(6-4x)}{x+1} } \\ \\ 3\ \textgreater \ 1 \\ \\ 2x-3\ \textgreater \ \frac{12-8x}{x+1} \\ \\ \frac{2x^2-3x+2x-3-12+8x}{x+1} \ \textgreater \ 0 \\ \\ \frac{2x^2+7x-15}{x+1} \ \textgreater \ 0 \\ \\ D=169 \\ \\ x_{1} =-5 \\ \\ x_{2} =1.5$

-----(-5)+++++(-1)------(1.5)+++++

x∈(-5;-1)U(1.5;+∞)