Question

Найдите первообразную функций: f(x)=sin+1; f(x)=1\x^3+3x; f(x)=x^5-3x^2; f(x)=x+3\x^6-cosx.

Answer 1

f(x)=x^5-3x^2=x^5+1/5+1-3x^2+1/2+1=x^6/6-3x^3/3=x^6-x^3