Question

Помогите пожалуйста с алгеброй!!!!Очень надо!!!!! срочно!!!! заранее спасибо♥

Answer 1

$\frac{2y}{a-b} = \frac{2y(a-b)}{(a-b)(a-b)} = \frac{2ay-2by}{(a-b)^2} \\ \\ \frac{-3x}{x+a} = \frac{-3x(x-a)}{(x+a)(x-a)} = \frac{-3x^2+3ax}{x^2-a^2} \\ \\ \frac{5a}{y-1} = \frac{5a(y^2+y*1+1^2)}{(y-1)(y^2+y*1+1^2)} = \frac{5ay^2+5ay+5a}{y^3 - 1^3} =\frac{5ay^2+5ay+5a}{y^3 - 1} \\ \\ \frac{4b}{a^2+ab+b^2} = \frac{4b(a-b)}{(a^2+ab+b^2)(a-b)} = \frac{4ab-4b^2}{a^3-b^3}$
$\frac{9y}{y-b} = \frac{9y}{-(b-y)} =- \frac{9y}{b-y} \\ \\ \frac{-5x}{x-10} = \frac{-5x}{-(10-x)} = \frac{5x}{10-x} \\ \\ \frac{-4p}{p+2} = \frac{-4p(2-p)}{(2+p)(2-p)} = \frac{-8p +4p^2}{2^2 -p^2} = \frac{4p^2 - 8p}{4-p^2}$