Question

Решите систему уравнений из Арифметики Диофанта

Answer 1

(
$(3 {y}^{2} ) + {y}^{2} = 10(3y - y) \\ 9 {y}^{2} + {y}^{2} = 20y \\ 10 {y}^{2} -20y = 0 \\ 10y(y - 2) = 0 \\ y1 = 0 \\ y2 = 2$
$y2 = 2$
$x1 = 3 \times y1 = 3 \times 0 = 0 \\ x2 = 3 \times y2 = 3 \times 2 = 6$