Question

Срочно помогите решить.

Answer 1

1)
$\sqrt{3} \times \sqrt{12} = \sqrt{3 \times 12} = \sqrt{36} = 6$
2)
$( \sqrt{19} - \sqrt{6} ) \times ( \sqrt{19} + \sqrt{6} ) = ( \sqrt{19} )^{2} - ( \sqrt{6} )^{2} = 19 - 6 = 13$
3)
$\frac{ \sqrt{24} }{ \sqrt{6} } = \sqrt{ \frac{24}{6} } = \sqrt{4} = 2$
4)
$\sqrt{8} + 2 \sqrt{2} = 2 \sqrt{2} + 2 \sqrt{2} = 4 \sqrt{2}$