Question

сократите алгебраическую дробь
3-3x/x^2-2x+1
(b-2)^3/(2-b)^2

Answer 1

$\frac{3-3x}{x^2-2x+1} = \frac{-3(x-1)}{x^2-2x*1+1^2} = \frac{-3(x-1)}{(x-1)^2} = \frac{-3}{x-1} = - \frac{3}{x-1} \\ \\ \frac{(b-2)^3}{(2-b)^2} = \frac{(b-2)(b-2)(b-2)}{-(b-2) * - (b-2)} = \frac{b-2}{(-1)*(-1)} = \frac{b-2}{1} =b-2$