Question

а) 3x^2+6y+3y^2=
б) x^3+8

Answer 1

$3x {}^{2} + 6y + 3y {}^{2} = 3( \times {}^{2} + 2y + y {}^{2} ) \\ x {}^{3} + 8 = (x + 2)(x {}^{2} - 2x + 4)$