Question

a)
12y^3
_____
-42y^5
в)
5а^2. 5a
_____ = ____
6a. 6

Answer 1

$\frac{12y {}^{3} }{ - 42y {}^{5} } = \frac{4}{ - 15y {}^{2} } = - \frac{4}{15y {}^{2} } \\ \\ \frac{5a {}^{2} }{6a} = \frac{5a}{6}\: \: \: \: \: \: \: \frac{5a}{6} = \frac{5a}{6}$