Question

найти значение выражения

Answer 1

$(*)tg(\alpha)*ctg(\alpha)=1\\ (*)2cos(a)sin(a)=sin(2a)\\ \\ 2tg(30\degree)ctg(30\degree)cos(30\degree)*\\*sin^3(30\degree)+\sqrt{3}tg(60\degree)= \\=2cos(30\degree)*sin(30\degree)*sin^2(30\degree)+\\+\sqrt{3}tg(60\degree)=\\sin(60\degree)*sin^2(30\degree)+\sqrt{3}tg(60\degree)=\\ =\sqrt{3}/2*1/4+(\sqrt{3})^2=3+\sqrt{3}/8$