Question

решите!!!!!!!!!!!!
$log_{2}(0.16)$
!!!!!!!!!!!

Answer 1

$log_{2}(0.16) = log_{2}\bigg(\frac{16}{100}\bigg)=\\ = log_{2}\bigg(\frac{4}{10}\bigg)^2=2log_{2}(0.4)\\ or \\ 2log_{2}\bigg(\frac{4}{10}\bigg)=\\ =2(log_{2}{4}-log_{2}{10}) =2(2-log_{2}{10})=\\ =4-log_{2}{100}$