Question

Помогите решить уравнение log5(4х−2)=1

Answer 1

$log5 (4x - 2) = 1 \\ \\ log5 (4x - 2) = 1 \times log5 \\ \\ log5 (4x - 2) = log5(5) \\ \\ 4x - 2 = 5 \\ \\ 4x = 5 + 2 \\ \\ 4x = 7 \\ \\ x = 7 \div 4 \\ \\ x = \frac{7}{4}$
Вот помогла