Question

определенный интеграл равен

Answer 1

$\int\limits^1_0 \bigg(8x-1\bigg)dx =(\frac{8x^2}{2}-x)\bigg |^1_0=\\=\bigg (4x^2-x\bigg)\bigg |^1_0=\\= (4-1)-(4*0-0)=3$