Question

$1)\frac{x + 2}{3} - 4x = 8 \\ 2)(3x + 1)^{2} - 9(x + 1) \times (x - 1) = 0$
Решите уравнения

Answer 1

1) x+2/3 - 4x=8
x+2-12x=24
-11x+2=24
-11x=24-2
-11x=22
x=-2
2)(3x+1)^2-9(x+1)(x-1)=0
9x^2 +6x+1-9(x^2 -1)=0
9x^2+6x+1-9x^2+9=0
6x+10=0
6x=-10
x=- 5/3