Question

№4
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Answer 1

$1)\; \; 4x^2+16x+11=4((x^2+4x)+11=4(x+2)^2-4)+11=\\\\=4(x+2)^2-16+11=4(x+2)^2-5\\\\ili:\; \; 4x^2+16x+11=(2x+4)^2-5\\\\2)\; \; \frac{1}{4}x^2-2x+13=\frac{1}{4}(x^2-8x)+13=\frac{1}{4}((x-4)^2-16)+13=\\\\=\frac{1}{4}(x-4)^2+9\\\\ili:\; \; \frac{1}{4}x^2-2x+13=(\frac{1}{2}x-2)^2+9\\\\3)\; \; 36x^2+72x+42=36(x^2+2x)+42=36((x+1)^2-1)+42=\\\\=36(x+1)^2+6\\\\ili:\; \; 36x^2+72x+42=(6x+6)^2+6\\\\4)\; \; 9x^2+12x-28=(3x)^2+2\cdot 2\cdot 3x+2^2-2^2-28=\\\\=(3x+2)^2-32$