Question

Найти значение выражения
sin(2п/3-п/6)

Answer 1

sin(2pi/3-pi/6)=sin(4pi/6-pi/6)=sin(3pi/6)=sin(pi/2)=1
sin(a-b)=sin(a)*cos(b)-sin(b)*cos(a)
sin(2pi/3-pi/6)=sin(2pi/3)*cos(pi/6)-cos(2pi/3)*sin(pi/6)=(sqrt(3)/2)*(sqrt(3)/2)-(-1/2)*(1/2)=(3/4)+(1/4)=(4/4)=1