Question

Найдите корень уравнения \frac{11}{x+3} =10

Answer 1

$\frac{11}{x + 3} = 10$
x ≠ -3
$11 = 10(x + 3) \\ 11 = 10x + 30 \\ - 10x = 30 - 11 \\ - 10x = 19 \\ x = - \frac{19}{10} = - 1 \frac{9}{10} = - 1.9$