Question

x(x-3)^3-x(x-2)^3=-19x

Answer 1

$\x(x-3)^3-x(x-2)^3=-19x\ x(x^3-9x^2+27x-27)-x(x^3-6x^2+12x-8)=-19x\ x^4-9x^3+27x^2-27x-x^4+6x^3-12x^2+8x=-19x\ -3x^3+15x^2=0\ -3x^2(x-5)=0\ x=0 vee x=5$

Answer 2

x(x-3)³-x(x-2)³=-19x

х(х³-9х²+27х-27)-х(х³-6х²+12х-8)=-19х

х⁴-9х³+27х²-27х-х⁴+6х³-12х²+8х=-19х

-3х³+15х²-19х =-19х

-3х³+15х²-19х + 19х = 0

-3х³+15х² = 0

-3х²(х-5)=0

х = 0  или х = 5

Ответ. х = 0, х = 5.