Question

решите систему уравнений x^2-y=16,x+y=4

Answer 1

$\left \{ {{x^2-y=16} \atop {x+y=4}} \right. \left \{ {{x^2+x-4=16} \atop {y=4-x}} \right. \\x^2+x-4=16\\x^2+x-20=0\\D=81\\x_1=4\\x_2=-5\\y_1=0\\y_2=9$