Question

$\frac{( - {9})^{4} \times {81}^{3} }{( - {3})^{17} }$

Answer 1

$\frac{(-9)^4*81^3}{(-3)^{17}}= \frac{(-3)^8*3^{12}}{(-3)^{17}} = \frac{3^{20}}{(3)^{-17}}=-3^{20-17}=-3^3=-27$