Question

Нужна помощь с задачей номер 20 (с решением)

Answer 1

$0.8(0.2+1)(0.2^2+1)(0.2^4+1)(0.2^8+1)+( 5^{-2} )^8= \\ \\ \frac{0.8(0.2-1)(0.2+1)(0.2^2+1)(0.2^4+1)(0.2^8+1)}{0.2-1} +( 5^{-2} )^8= \\ \\ \frac{0.8(0.2^2-1)(0.2^2+1)(0.2^4+1)(0.2^8+1)}{0.2-1}+( 5^{-2} )^8= \\ \\ \frac{0.8(0.2^4-1)(0.2^4+1)(0.2^8+1)}{0.2-1}+( 5^{-2} )^8= \\ \\ \frac{0.8(0.2^8-1)(0.2^8+1)}{0.2-1}+( 5^{-2} )^8= \\ \\ \frac{0.8( 0.2^{16} -1)}{-0.8}+( 5^{-2} )^8=- ( \frac{1}{5} )^{16} +1+ 5^{-16} =-5^{-16}+1+5^{-16}=1$