Question

log_x+1 (2x^2-5x-7)=2

Answer 1

${(x + 1)}^{2} = 2 {x}^{2} - 5x - 7 \\ {x}^{2} + 2x + 1 = 2 {x}^{2} - 5x - 7 \\ - {x}^{2} + 7x + 8 = 0 \\ x = - 1 \\ x = 8$