Question

32 корня из 3 * tg(-600градусов)

Answer 1

$32\sqrt{3}\cdot tg(-600^\circ )=32\sqrt3\cdot tg(-720^\circ +120^\circ)=\\\\=32\sqrt3\cdot tg120^\circ =32\sqrt3\cdot tg(180^\circ -60^\circ )=\\\\=32\sqrt3\cdot (-tg60^\circ )=-32\sqrt3\cdot \sqrt3=-32\cdot 3=-96$