Question

Найдите корень неравенства

Answer 1

${(x - 3)}^{ {x}^{2} - 5x + 6 } > {(x - 3)}^{0} \\ {x}^{2} - 5x + 6 > 0 \\ nayidyom \: korni \: uravneniya \\ {x}^{2} - 5x + 6 = 0 \\ po \: teoreme \: vietta \\ x1 = 2 \\ x2 = 3$
(-°°; 2) (3;+°°)