Question

A1 пожалуйста помогите

Answer 1

1) S[0;1] (4-x^2)dx = (4x - (1/3)*x^3)[0;1] = 4 - (1/3) - 0 = 11/3.
2) S[0;1] (-x^2 -2x +3)dx = (-(1/3)*x^3 - x^2 + 3x)[0;1] = -(1/3) - 1 + 3 - 0 = 
= 2 - (1/3) = 5/3.