Question

Log36 8 =n, найти log9 324

Answer 1

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Answer 2

$\mathtt{\log_{36}8=\frac{3}{2}\log_62=\frac{3}{2\log_26}=\frac{3}{2\log_2(3*2)}=\frac{3}{2(1+\log_23)}=n\to\log_23=\frac{3-2n}{2n};~}\\\mathtt{\log_9324=\log_9(81*4)=2+\log_32=2+\frac{2n}{3-2n}=\frac{6-2n}{3-2n}}$