Question

1-sin^2a/1-cos^2a+tg(a)ctg(a)

^2-квадрат
а-альфа

Answer 1

1 - Sin²α = Cos²α
1 - Cos²α = Sin²α
tgα * Ctgα = 1

$\frac{1-Sin ^{2} \alpha }{1-Cos ^{2} \alpha } +tg \alpha Ctg \alpha = \frac{Cos ^{2} \alpha }{Sin ^{2} \alpha }+1=Ctg ^{2} \alpha +1= \frac{1}{Sin ^{2} \alpha }$