Question

Помогите решить пожалуйста с подробным описанием

Answer 1

$\sqrt{5-2\sqrt{6}}=\sqrt{(\sqrt{3}-\sqrt{2})^2}=|\sqrt{3}-\sqrt{2}|=\sqrt{3}-\sqrt{2};$

$5+2\sqrt{6}=(\sqrt{3}+\sqrt{2})^2;$

$\scriptstyle -49+20\sqrt{6}=-(5^2-2\cdot 5\cdot (2\sqrt{6})+(2\sqrt{6})^2)= -(5-2\sqrt{6})^2=-(\sqrt{3}-\sqrt{2})^4;$

$\sqrt{27}-3\sqrt{18}+3\sqrt{12}-\sqrt{8} =3\sqrt{3}-9\sqrt{2}+6\sqrt{3}-2\sqrt{2}= 9\sqrt{3}-11\sqrt{2};$

$a=-\frac{(\sqrt{3}-\sqrt{2})(\sqrt{3}+\sqrt{2})^2(\sqrt{3}-\sqrt{2})^4}{9\sqrt{3}-11\sqrt{2}}= -\frac{(\sqrt{3}-\sqrt{2})^3((\sqrt{3})^2-(\sqrt{2})^2)^2}{(\sqrt{3}-\sqrt{2})^3}=-1$

Ответ: 1 (истинны высказывания б, в, г)