Question

ПОМОГИТЕ ДАЮ МНОГО БАЛОВ

Answer 1

(2x-3)(2x+3)=2(x+3/2)(x+1)
(2x-3)(2x+3)-(2x+3)(x+1)=0
(2x+3)(2x-3-x-1)=0
(2x+3)(x-4)=0
x₁=-1.5
x₂=4

ОТВЕТ {-1.5;4}

Answer 2

$(2x-3)(2x+3)=2(x+\frac{3}{2})(x+1)$
$4x^{2} -9 = (2x+3)(x+1)$
$4x^{2} -9 = 2x^{2}+2x+3x+3$
$4x^{2} -9 = 2x^{2}+5x+3$
$4x^{2} -9 - 2x^{2} - 5x-3=0$
$2x^{2}-12-5x=0$
$2x^{2} -5x-12=0$
$\frac{-(-5)± \sqrt{(-5)^{2}-4*2*(-12)}}{2*2}$
$x= \frac{5± \sqrt{25+96}}{4}$
$x= \frac{5± \sqrt{121}}{4}$
$x=\frac{5±11}{4}$
$x=\frac{5+11}{4}$
$x=\frac{5-11}{4}$
$x=4$
$x = -\frac{3}{2}$