Question

$64 {a}^{3} - \frac{1}{27} {b}^{3 }$

Answer 1

$64a^3-\frac{1}{27}b^3=(4a-\frac{1}{3}b)(16a^2+1\frac{1}{3}ab+\frac{1}{9}b^2)$

Answer 2

$64 {a}^{3} - \frac{1}{27} {b}^{3} = (4a - \frac{1}{3} b)(16 {a}^{2} + \frac{4}{3} ab + \frac{1}{9} {b}^{2} )$