Предмет: Алгебра, автор: костя111

Помогите пожалуйста! ( sqrt{ sqrt{3}+ sqrt{2}  } - sqrt{ sqrt{3}- sqrt{2}  } )*(  sqrt{ sqrt{3}+ sqrt{2}  }+ sqrt{ sqrt{3}- sqrt{2}  } ) ^{-1}   +  sqrt{ sqrt{( sqrt{5}- frac{5}{2}) ^{2}   }- sqrt[3]{( frac{3}{2}- sqrt{5) } ^{3}  }  }  }

Ответы

Автор ответа: Yena
0
(sqrt{sqrt{3}+sqrt{2}}-sqrt{sqrt{3}-sqrt{2}})*(sqrt{sqrt{3}+sqrt{2}}+sqrt{sqrt{3}-sqrt{2}}) ^{-1}  +sqrt{sqrt{(sqrt{5}-frac{5}{2})^{2}}-sqrt[3]{(frac{3}{2}-sqrt{5)}^{3}}}}=\ 
=frac{sqrt{sqrt{3}+sqrt{2}}-sqrt{sqrt{3}-sqrt{2}}}{sqrt{sqrt{3}+sqrt{2}}+sqrt{sqrt{3}-sqrt{2}}}  +sqrt{|sqrt{5}-frac{5}{2}|-frac{3}{2}+sqrt{5)}}=\
=frac{sqrt{sqrt{3}+sqrt{2}}-sqrt{sqrt{3}-sqrt{2}}}{sqrt{sqrt{3}+sqrt{2}}+sqrt{sqrt{3}-sqrt{2}}}  +sqrt{frac{5}{2}-sqrt{5}-frac{3}{2}+sqrt{5}}=\
=frac{sqrt{sqrt{3}+sqrt{2}}-sqrt{sqrt{3}-sqrt{2}}}{sqrt{sqrt{3}+sqrt{2}}+sqrt{sqrt{3}-sqrt{2}}} +1=frac{(sqrt{sqrt{3}+sqrt{2}}-sqrt{sqrt{3}-sqrt{2}})^2}{(sqrt{sqrt{3}+sqrt{2}}+sqrt{sqrt{3}-sqrt{2}})(sqrt{sqrt{3}+sqrt{2}}-sqrt{sqrt{3}-sqrt{2}})} +1=\
=frac{(sqrt{sqrt{3}+sqrt{2}})^2-2sqrt{sqrt{3}+sqrt{2}}*sqrt{sqrt{3}-sqrt{2}}+(sqrt{sqrt{3}-sqrt{2}}))^2}{(sqrt{sqrt{3}+sqrt{2}})^2-(sqrt{sqrt{3}-sqrt{2}})^2} +1=
=frac{sqrt{3}+sqrt{2}-2+sqrt{3}-sqrt{2}}{sqrt{3}+sqrt{2}-sqrt{3}+sqrt{2}}+1\
=frac{2sqrt{3}-2}{2sqrt{2}}+1=frac{2sqrt{3}-2+2sqrt{2}}{2sqrt{2}}=frac{sqrt{3}-1+sqrt{2}}{sqrt{2}}
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