Question

срочно помогите 6 номер

Answer 1

б) 16с²-49=0
16с²=49
с²=49\16
с1=7\4
с2=-7\4
а) (4х-3)(4х+3)-(4х-1)²=3х
16х²-9-(16х²-8х+1)=3х
16х²-9-16х²=8х-1=3х
-10=8х=3х
8х-3х=10
5х=10
х=2

Answer 2

$a) \\ (4x-3)(4x+3)-(4x-1)^2=3x \\ 16x^2-9-16x^2+8x-1=3x \\ 5x=10 \\ x=2$

$b) \\ 16c^2-49=0 \\ c^2= \frac{49}{16} \\ \\ c=\pm \frac{7}{4}$