Question

2х-(4+2х)^2, 8х-(6х+5х)^2 ,10у+(3х+у)^2 .решите пж.только быстрее пжжж
дам 15 баллов)

Answer 1

2x-(4+2x)^2=2x-(16+2*4*2x+4x^2)=2x-16-16x-4x^2=-16-14x-4x^2=-16-2x(7+2x)=-2(8+x(7+2x));
8x-(6x+5x)^2=8x-(11x)^2=8x-121x^2;
10y+(3x+y)^2=10y+9x^2+2*3x*y+y^2=9x^2+6xy+10y+y^2=3x*(3x+2y)+y*(10+y);