Question

Решите уравнение( через дискриминант)
3x^2-4x-5=0

Answer 1

$3x^{2} - 4x - 5 = 0$
a = 3, b = -4 , c = -5
D = $b^{2} - 4ac = -4*(-4) + 60 = 76$
$\sqrt{D} = \sqrt{76}$
x1 = $\frac{-b - \sqrt{D} }{2a}$ = $\frac{4- \sqrt{76} }{6}$ 
x2 = $\frac{4+ \sqrt{76} }{6}$