Question

Найдите производное функции
(x^3 -7/3-4x^4)'

Answer 1

$y=\frac{x^3-7}{3-4x^4}\\\\y'=\frac{3x^2\cdot (3-4x^4)-(x^3-7)\cdot (-16x^3)}{(3-4x^4)^2}=\frac{9x^2-12x^6+16x^6-112x^3}{(3-4x^4)^2}=\\\\=\frac{9x^2+4x^6-112x^3}{(3-4x^4)^2}$