Question

Покажите решение и ответ

Answer 1

(1-n)(n^2+1)(n-1)-4n(3n-7)(2n+3)-2n(3n-5)=(n^2+1−n^3−n)(n−1)+(−12n^2+28n)(2n+3)−6n^2+10n=n^3-n^2+n−1−n^4+n^3−n^2+n−24n^3−36n^2+56n^2+84n−6n^2+10n=−n^4−22n^3+12n^2+96n−1